Question

Of the 36 students in a certain class, 10 are in the chess club and 13 are in the bridge club. If 20 of the students are not in either club, how many of the students are in only one of the two clubs?A. 7B. 9C. 14D. 16E. 23

Answer 1

There are 9 students in only one of the two clubs.

Step-by-step explanation:

Since we have given that

Number of students = 36

Number of students are in chess club = 10

Number of students are in bridge club = 13

Number of students are not in either club = 20

So, Number of students in both the club is given by

$Total=n(chess)+n(bridge)-n(both)+n(neither)\\\\36=10+13-n(both)+20\\\\36=43-n(both)\\\\36-43=n(both)\\\\-7=-n(both)\\\\n(both)=7$

Number of students only in chess = 10-7 =3

Number of students only in bridge = 13-7=6

Hence, there are 3+6=9 students in only one of the two clubs.