Ex) A nursery plants a new tree and attaches a guy wire to help support the tree

while its roots take hold. An eight foot wire is attached to the tree and to a stake in

the ground. From the stake in the ground the angle of elevation of the connection

with the tree is 42º. Find to the nearest tenth of a foot, the height of the connection

point on the tree.

Respuesta :

Answer:

d =   5,35 ft

Step-by-step explanation: See annex

Figure in  annex is clear,  

sin ∠42⁰  = d / 8

And

sin ∠42⁰   =  0.669

d/8   =  0,669

d  =  0,669*8  

d =   5,35 ft

Answer:

a ≈ 5.4 ft

Step-by-step explanation:

A guy wire is used to hold a tree firmly to the ground to avoid bending or falling due to earth natural phenomenon like wind.

The guy wire is tied to a stake and attached to the tree. The illustration above forms a right angle triangle. The angle of elevation from the stake in the ground with the tree is 42°.

The tree forms the opposite side of the right angle triangle starting from the point the guy wire was attached down to the base of the tree. The guy wire attached from the tree to the stake forms the hypotenuse of the right angle triangle.

The height of the connection point on the tree is the height of the tree starting from where the guy wire was tied to the tree to the base. Let us call the height a.

hypotenuse = 8 ft

opposite side(a) = ?

angle of elevation = 42°

Using the SOHCAHTOA principle

sin ∅ = opposite/hypotenuse

sin 42° = a/8

cross multiply

a = 8 sin 42°

a = 8 ×  0.6691306064

a =  5.3530448509

a ≈ 5.4 ft

ACCESS MORE