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Suppose the true proportion of voters in the county who support a new fire district is .65. Consider the sampling distribution for the proportion of supporters with sample size n=117.

What is the mean of the distribution?

What is the standard deviation of this distribution?

Respuesta :

Answer:

The mean of the distribution = 76.05

The standard deviation of this distribution = 5.159

Step-by-step explanation:

Given:

The true proportion of voters in the county who support a new fire district is =0.65

sample size n=117.

Solution:

The mean of the distribution:

The mean of the distribution is given by  n * p

where

n= sample size

p=  probability of success on an individual trial.

Substituting the values , we get

Mean=117 *0.65

Mean=76.05

Standard deviation of this distribution:

[tex]\sigma=\sqrt{np(1-p)[/tex]

[tex]\sigma=\sqrt{117(0.65)(1-0.65)[/tex]

[tex]\sigma=\sqrt{117(0.65)(0.35)[/tex]

[tex]\sigma=\sqrt{26.6175[/tex]

[tex]\sigma= 5.159[/tex]

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