Question

In the equation, p and t are constants. What is the value of p? 4x2 − 9 = (px + t)(px − t) A) 2 B) 3 C) 4 D) 9

Answer 1

Answer:

A) 2

Step-by-step explanation:

4x² - 9 = (px + t)(px - t)

Using formula a² - b² = (a-b)(a+b)

4x² - 9 = (2x)² - 3² = (2x - 3)(2x+3),

so

(px + t)(px - t) = (2x - 3)(2x + 3).

We can see that p = 2, and t = 3.

Answer 2

The value of p should be 2.

Given that,

• P and t are constants.

And,

• $4x^2 - 9 = (px + t) (px - t)$

Now we use the following formula to determine the value of p

We know that

$a^2 - b^2 = (a - b) (a + b)\\\\4x^2 - 9 = (2x)^2 - 3^2 = (2x -3) (2x + 3)$

Thus,

(px + t ) (px - t) = (2x - 3) (2x + 3)

So, here p = 2, and t = 3

Therefore we can conclude that the value of p is 2

Learn more about the algebraic equations here: brainly.com/question/12694668