Answer:
θ = 28.94 rad
Explanation:
The uniformly accelerated circular movement a circular path movement in which the angular acceleration is constant.
Kinematics to the drill
We apply the equations of circular motion uniformly accelerated :
θ = ω₀*t + (1/2)*α*t² Formula (1)
Where:
θ : Angular displacement during that time interval (rad)
α : angular acceleration (rad/s²)
t : time interval (s)
ω₀ : initial angular speed ( rad/s)
Data
ω₀ = 5.79 rad/s
α = 0.321 rad/s²
t = 4.45 s
Angular displacement of the drill during that time interval t = 4.45 s
We replace data in the formula (1)
θ = ω₀*t + (1/2)*α*t²
θ = (5.79)*(4.45) + (1/2)* (0.321)*(4.45)²
θ = 25.7655+3.178
θ = 28.94 rad
