Answer:
Normality = 0.1 N
Explanation:
Data given:
weight of Na₂CO₃ = 5.3g/L
Normality: ?
Normality:
It is the expression of concentration for a solution.
Normality is the gram equivalent of a compound in the per liter of solution.
Equivalent:
one equivalent can react with hydrogen ion or replace hydrogen ion.
Formula for Normality:
Normality = gram equivalent of solute / volume of solution in L ....(1)
we know
gram equivalent of solute = weight/ equivalent weight ....... (2)
So by combining equation 1 and 2 the formula will be
N = weight / equivalent weight / volume of solution in L ........ (3)
Now first we have to find equivalent weight.
As in Na₂CO₃ there are 2 Na that can replace hydrogen ion in a solution,
So, we have 2 equivalent
The Molar mass of the Na2CO3 = (23x2 + 12 + 16x3)
Na2CO3 = 106 g/mol
Now to find equivalent weight:
equivalent weight: molar mass / no. of equivalent (n)
equivalent weight: 106 g/mol / 2
equivalent weight: 53 g/mol
Put the values in Equation 2:
gram equivalent = weight/ eq. weight
gram equivalent = 5.3 / 53
gram equivalent = 0.1
Now put this value of gram equivalent in equation 1
Normality = gram equivalent of solute / volume of solution in L
Normality = 0.1 /1L
Normality = 0.1 N
So the Normality of the solution is 0.1N
