Question

What is the amplitude, period, and phase shift of f(x) = −2 sin(3x − π) − 1?

Answer 1

Answer:

see explanation

Step-by-step explanation:

The standard form of the sine wave function is

y = a sin (bx + c) + d

where amplitude = | a |, period = $\frac{2\pi }{b}$

phase shift = - $\frac{c}{b}$ and d is the vertical shift

Here a = - 2, b = 3 and c = - π

Hence

amplitude = | - 2 | = 2

period = $\frac{2\pi }{3}$ and

phase shift = - $\frac{-\pi }{3}$ = $\frac{\pi }{3}$