Question

A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity

Answer 1

Answer:

9.17 m/s

Explanation:

Impulse = change in momentum

FΔt = mΔv

(166 N) (0.39 s) = (7.06 kg) Δv

Δv = 9.17 m/s

Answer 2

Answer:

$\displaystyle 9,1829787234\:m/s$

Explanation:

$\displaystyle \frac{[0,39][166]}{7,05} = \frac{7,05v}{7,05} \\ \\ 9,1829787234 ≈ v$

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