A 10-kg box is pushed up a plane inclined at 37º with the horizontal. The box starts from rest and is pushed 5 m along the incline with a uniform acceleration of 2 m/s2. The coefficient of kinetic friction is 0.20 and the pushing force is parallel to the plane. The increase in the potential energy of the box is _____

Respuesta :

Answer:

U = 294 J

Explanation:

The potential energy has as a formula

    ΔU = m g y - gm y₀

Where the value of y₀ can be zero if we take the reference system in the lower part of the plane.

Let's look for height with trigonometry

    sin 37 = Y / L

     y = L sin 37

    y = 5 sin37

    y = 3.00 m

Let's calculate

    U = m g and

    U = 10 9.8 3

    U = 294 J

This the potential energy change, it doesn't matter if it goes up with constant speed

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