Question

Metal-X = Molybdenum


Metal-Y = Iron



Metal-X forms a substitutional solid solution with Metal-Y. Compute the number of Metal-X atoms per cubic centimetier for a Metal-Y---Metal-X alloy that contains 33wt% Metal-X and 67 wt% Metal-Y.

Answer 1

Answer:

there are two Mo atoms per seven Fe atoms

Explanation:

The metal X = Molybdenum

Metal Y = Iron

The atomic weight of

Mo = 96 g/ mol

Fe = 56 g/mol

The weight ratio of given metals is

Mo = 33%

Fe =67%

Let us calculate the moles of each metal in 100g of sample.

$mole=\frac{mass}{atomicmass}$

$Mole(Mo)=\frac{33}{96}= 0.34$

$mole(Fe)=\frac{67}{56}=1.2$

Thus metal atom ratio =$0.34:1.2 = 2:7$

Thus there are two Mo atoms per seven Fe atoms