Question

A 50 cm-long metal rod rotates about the z-axis at 90 revolutions per minute, with one end fixed at the origin. if b = z^2 × 10−4 t, determine the emf induced in the rod

Answer 1

Answer:

$EMF = 0.236\times 10^{-3}$

Explanation:

As we know that induced EMF in rotating rod is given as

$EMF = \frac{1}{2}B\omega L^2$

here we know that

$B = 2 \times 10^{-4} T$

L = 0.50 m

$\omega = 2\pi f$

$\omega = 2\pi (\frac{90}{60})$

$\omega = 3\pi$

now we have

$EMF = \frac{1}{2}(2\times 10^{-4})(3\pi)(0.50)^2)$

$EMF = 0.236\times 10^{-3}$