Question

A soccer ball has a mass of 0.40 kg. Initially, it is moving to the left at 20m/s, but then it is kicked and given a velocity of 45 degrees upward and to the right, with a magnitude of 30m/s. Find the impulse of the net force and the average net force, assuming a collision time of .010 seconds.

Answer 1

Answer:

Impulse = 18.53 kg m / s

Net force = 1853N

Explanation:

Mass of the ball, m = 0.4 kg

Initial velocity = 20 m/s horizontally left

Final velocity = 30 m/s at 45 degrees from horizontal

Time of collision = 0.010 s

Check attachment to see full explanation

Answer 2

The impulse and the average net force is 16.484 Ns and 1648.4 N respectively.

To calculate the impulse of the ball, we use the formula below.

Formula:

• I = m(v-u).............. Equation 1

Where:

• I = impulse of the net force
• m = mass of the ball
• u = initial velocity of the ball
• v =  final velocity of the ball

From the question,

Given:

• m = 0.40 kg
• u = -20 m/s (to the left)
• v = 30cos45° (to the right) = 21.21 m/s.

Substitute these values into equation 1

• I = 0.4[21.21-(20)]
• I = 0.4(21.21+20)
• I = 0.4(41.21)
• I = 16.484 Ns.

To calculate the average force, we use the formula below.

• F = I/t............. Equation 2

Where:

• F = Average force
• t = time.

From the question,

Given:

• I = 16.484 Ns
• t = 0.01 s

Substitute these values into equation 1

• F = 16.484/0.01
• F = 1648.4 N

Hence, The impulse and the average net force is 16.484 Ns and 1648.4 N respectively.

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