Question

Draw all of the monochlorination products that you might obtain from the free-radical chlorination of ethylcyclopropane.You do not have to consider stereochemistry.Draw one structure per sketcher. Add additional sketchers using the dropdown menu in the bottom right corner.Separate multiple products using the + sign from the dropdown menu.

Answer 1

Answer:

-) (2-chloroethyl)cyclopropane

-) (1-chloroethyl)cyclopropane

-) 1-chloro-2-ethylcyclopropane

-) 1-chloro-1-ethylcyclopropane

Explanation:

The monochlorination are products in which Cl is added only 1 time. Now, in the ethylcyclopropane we will have 5 carbons, so we will have 5 options for monochlorination (see figure 1). But, for carbons 2 and 3 we will have equivalent structures, therefore at the end, we will have only 4 possible structures. In carbon 5, carbon 4, carbon 3 and carbon 1 (see figure 2).