Respuesta :
Answer:
1) 1.092x10⁻¹² M
2) 4.89x10⁻⁶ M
3) Ag₃PO₄
4) Yes, it is.
Explanation:
1) The dissolution reaction of AgI is:
AgI(s) ⇄ Ag⁺(aq) + I⁻(aq)
The constant of equilibrium Kps is:
Kps = [Ag⁺]*[I⁻]
So, the minimum concentration of Ag⁺ is that one in equilibrium
8.30x10⁻¹⁷ = [Ag⁺]*7.60x10⁻⁵
[Ag+] = 1.092x10⁻¹² M
2) The dissolution reaction of Ag₃PO₄ is:
Ag₃PO₄(s) ⇄ 3Ag⁺(aq) + PO₄³⁻(aq)
The constant of equilibrium, Kps is:
Kps = [Ag⁺]³*[PO₄³⁻]
So, the minimum concentration of Ag⁺ is that one in equilibrium
8.90x10⁻¹⁷ = [Ag⁺]³*0.760
[Ag⁺]³ = 1.171x10⁻¹⁶
[Ag⁺] = 4.89x10⁻⁶ M
3) Because Ag₃PO₄ needs less Ag⁺ to precipitated, it will precipitate first.
4) To see if the separation will occur, let's verify is the ratio of the molar concentration of Ag⁺ for the substances is less then 0.1%:
(1.092x10⁻¹²)/(4.89x10⁻⁶) * 100% = 2.23x10⁻⁵ %
So, the separation is complete.
The Ksp is used to denote the extent of dissolution of compounds in water.
1) The equilibrium for the dissolution of AgI is set up as follows:
AgI(s) ⇄ Ag⁺(aq) + I⁻(aq)
Hence;
Ksp = [Ag⁺] [I⁻]
At equilibrium, the minimum concentration of Ag⁺ is
8.30x10⁻¹⁷ = [Ag⁺]*7.60x10⁻⁵
[Ag+] = 1.092x10⁻¹² M
2) The equilibrium for the dissolution of Ag₃PO₄ is set up as follows:
Ag₃PO₄(s) ⇄ 3Ag⁺(aq) + PO₄³⁻(aq)
Hence:
Ksp = [Ag⁺]³*[PO₄³⁻]
At equilibrium, the minimum concentration of Ag⁺ is
8.90x10⁻¹⁷ = [Ag⁺]³*0.760
[Ag⁺]³ = 1.171x10⁻¹⁶
[Ag⁺] = 4.89x10⁻⁶ M
3) The salt that is expected to precipitate first is Ag₃PO₄.
4) In order to determine if the separation is complete;
(1.092x10⁻¹²)/(4.89x10⁻⁶) * 100% = 2.23x10⁻⁵ %
This is less than 0.10% hence the separation is complete.
Learn more about Ksp: https://brainly.com/question/953809