Respuesta :

Answer:

[tex]25x+10y+18=0[/tex]

Step-by-step explanation:

We are given that a rectangle in which the equation of one side is given by

[tex]2x-5y=9[/tex]

We have to find the equation of another side of the rectangle.

We know that the adjacent sides of rectangle are perpendicular to each other.

Differentiate the given equation w.r.t.x

[tex]2-5\frac{dy}{dx}=0[/tex]   ([tex]\frac{dx^n}{dx}=nx^{n-1}[/tex])

[tex]5\frac{dy}{dx}=2[/tex]

[tex]\frac{dy}{dx}=\frac{2}{5}[/tex]

Slope of the given side=[tex]m_1=\frac{2}{5}[/tex]

When two lines are perpendicular then

Slope of one line=[tex]-\frac{1}{Slope\;of\;another\;line}[/tex]

Slope of another side=[tex]-\frac{5}{2}[/tex]

Substitute x=0 in given equation

[tex]2(0)-5y=9[/tex]

[tex]-5y=9[/tex]

[tex]y=-\frac{9}{5}[/tex]

The equation of given side is passing through the point ([tex]0,-\frac{9}{5})[/tex].

The equation of line passing through the point [tex](x_1,y_1)[/tex] with slope m is given by

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the values then we get

[tex]y+\frac{9}{5}=-\frac{5}{2}(x-0)=-\frac{5}{2}x[/tex]

[tex]y=-\frac{5}{2}x-\frac{9}{5}[/tex]

[tex]y=\frac{-25x-18}{10}[/tex]

[tex]10y=-25x-18[/tex]

[tex]25x+10y+18=0[/tex]

Hence, the equation of another side of rectangle is given by

[tex]25x+10y+18=0[/tex]

Answer:

y=2/5x-9

I just answered this and got it right.

Step-by-step explanation:

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