Respuesta :
Answer:
[tex]25x+10y+18=0[/tex]
Step-by-step explanation:
We are given that a rectangle in which the equation of one side is given by
[tex]2x-5y=9[/tex]
We have to find the equation of another side of the rectangle.
We know that the adjacent sides of rectangle are perpendicular to each other.
Differentiate the given equation w.r.t.x
[tex]2-5\frac{dy}{dx}=0[/tex] ([tex]\frac{dx^n}{dx}=nx^{n-1}[/tex])
[tex]5\frac{dy}{dx}=2[/tex]
[tex]\frac{dy}{dx}=\frac{2}{5}[/tex]
Slope of the given side=[tex]m_1=\frac{2}{5}[/tex]
When two lines are perpendicular then
Slope of one line=[tex]-\frac{1}{Slope\;of\;another\;line}[/tex]
Slope of another side=[tex]-\frac{5}{2}[/tex]
Substitute x=0 in given equation
[tex]2(0)-5y=9[/tex]
[tex]-5y=9[/tex]
[tex]y=-\frac{9}{5}[/tex]
The equation of given side is passing through the point ([tex]0,-\frac{9}{5})[/tex].
The equation of line passing through the point [tex](x_1,y_1)[/tex] with slope m is given by
[tex]y-y_1=m(x-x_1)[/tex]
Substitute the values then we get
[tex]y+\frac{9}{5}=-\frac{5}{2}(x-0)=-\frac{5}{2}x[/tex]
[tex]y=-\frac{5}{2}x-\frac{9}{5}[/tex]
[tex]y=\frac{-25x-18}{10}[/tex]
[tex]10y=-25x-18[/tex]
[tex]25x+10y+18=0[/tex]
Hence, the equation of another side of rectangle is given by
[tex]25x+10y+18=0[/tex]
Answer:
y=2/5x-9
I just answered this and got it right.
Step-by-step explanation: