Answer: 0.0274 M
Explanation:-
The balanced chemical solution is:
[tex]NH_4OH(aq)+HCl(aq)\rightarrow NH_4Cl(aq)+H_2O(l)[/tex]
According to the neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]HCl[/tex] solution = 0.117 M
[tex]V_1[/tex] = volume of [tex]HCl[/tex] solution = 23.4 ml
[tex]M_2[/tex] = molarity of [tex]NH_4OH[/tex] solution = ?
[tex]V_2[/tex] = volume of [tex]NH_4OH[/tex] solution = 100.0 ml
[tex]n_1[/tex] = valency of [tex]HCl[/tex] = 1
[tex]n_2[/tex] = valency of [tex]NH_4OH[/tex] = 1
[tex]1\times 0.117M\times 23.4=1\times M_2\times 100.0[/tex]
[tex]M_2=0.0274[/tex]
Therefore, the concentration of ammonia in a solution will be 0.0274 M
