Question

A microscope is focused on an amoeba. Part A When a 0.15-mm-thick cover glass (n=1.50) is placed over the amoeba, by how far must the microscope objective be moved to bring the organism back into focus? Express your answer in millimeters. ΔsΔ s = nothing mm Request Answer Part B Must it be raised or lowered?

Answer 1

Answer:

$\Delta s=0.05\ mm$

∵The apparent depth is less therefore we need to raise the objective away from the placed object.

Explanation:

Given:

Real depth, $d_r=0.15\ mm$

refractive index of the medium, $n=1.5$

We know,

$n=\frac{d_r}{d_a}$

where:

$d_a=$ apparent depth of the object

$\therefore 1.5=\frac{0.15}{d_a}$

$d_a=0.1\ mm$

Now, the difference in the real and apparent depths:

$\Delta s=d_r-d_a$

$\Delta s=0.05\ mm$

∵The apparent depth is less therefore we need to raise the objective away from the placed object.

Answer 2

ΔS = 0.05m makes the apparent depth is less therefore we need to raise the objective away from the placed object.

What is Depth?

This is defined as the measurement from top to bottom or from front to back.

dr = 0.15mm

n =  dr/da

where da is apparent depth of object.

1.5 = 0.15/da

 = 0.1mm

The difference in the real and apparent depths(dr-da) = 0.05mm.

The apparent depth is less therefore we need to raise the objective away from the placed object.

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