Question

An ideal gas at 0?C consists of 1.0×1023 atoms. 13 J of thermal energy are added to the gas.

Answer 1

Answer:

The temperature is 18.83°C.

Explanation:

Given that,

Potential energy = 13 J

Suppose we need to find the new temperature in degrees C

Let new temperature be T.

We need to calculate the temperature

Using formula of temperature

$\Delta U = \dfrac{1}{2}\times R\times n\times \Delta T$

Where, $\Delta U$ = change in potential energy

$\Delta T$ = change in temperature

R = gas constant

n = number of moles

Put the value into the formula

$13=\dfrac{1}{2}\times8.314\times\dfrac{1.0\times10^{23}}{6.023\times10^{23}}\times(T-0)$

$T=\dfrac{13\times2\times6.023\times10^{23}}{8.314\times1.0\times10^{23}}$

$T=18.83^{\circ}C$

Hence, The temperature is 18.83°C.