Respuesta :
Answer:
The Riemann sum equals -10.
Step-by-step explanation:
The right Riemann Sum uses the right endpoints of a sub-interval:
[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)[/tex]
where
[tex]\Delta{x}=\frac{b-a}{n}[/tex]
To find the Riemann sum for [tex]\int\limits^{4}_{-6} {3x-1} \, dx[/tex] with n = 5 rectangles, using right endpoints you must:
We know that a = -6, b = 4 and n = 5, so
[tex]\Delta{x}=\frac{4-\left(-6\right)}{5}=2[/tex]
We need to divide the interval −6 ≤ x ≤ 4 into n = 5 sub-intervals of length [tex]\Delta{x}=2[/tex]
[tex]a=\left[-6, -4\right], \left[-4, -2\right], \left[-2, 0\right], \left[0, 2\right], \left[2, 4\right]=b[/tex]
Now, we just evaluate the function at the right endpoints:
[tex]f\left(x_{1}\right)=f\left(-4\right)=-13=-13[/tex]
[tex]f\left(x_{2}\right)=f\left(-2\right)=-7=-7[/tex]
[tex]f\left(x_{3}\right)=f\left(0\right)=-1=-1[/tex]
[tex]f\left(x_{4}\right)=f\left(2\right)=5=5[/tex]
[tex]f\left(x_{5}\right)=f(b)=f\left(4\right)=11=11[/tex]
Finally, just sum up the above values and multiply by 2
[tex]2(-13-7-1+5+11)=-10[/tex]
The Riemann sum equals -10
The Riemann sum for [tex]f(x) = 3\cdot x -1[/tex], [tex]-6 \le x\le 4[/tex] with five subintervals is -10.
The expression for the Riemann sum with right endpoints is described below:
[tex]S = \Delta x \cdot \Sigma\limits_{i=1}^{n} f(a+i\cdot \Delta x)[/tex] (1)
[tex]\Delta x = \frac{b-a}{n}[/tex] (2)
Where:
- [tex]a[/tex] - Lower bound.
- [tex]b[/tex] - Upper bound.
- [tex]n[/tex] - Number of subintervals.
- [tex]i[/tex] - Index.
- [tex]f(x)[/tex] - Function.
- [tex]S[/tex] - Riemann sum.
- [tex]\Delta x[/tex] - Length of the subinterval.
If we know that [tex]a = -6[/tex], [tex]b = 4[/tex], [tex]f(x) = 3\cdot x -1[/tex] and [tex]n = 5[/tex], then the Riemann sum is:
[tex]\Delta x = \frac{4-(-6)}{5}[/tex]
[tex]\Delta x = 2[/tex]
[tex]S = 2\cdot [f(-4)+f(-2)+f(0)+f(2)+f(4)][/tex]
[tex]S = 2\cdot (-13-7-1+5+11)[/tex]
[tex]S = -10[/tex]
The Riemann sum for [tex]f(x) = 3\cdot x -1[/tex], [tex]-6 \le x\le 4[/tex] with five subintervals is -10.
We kindly invite to chech this question on Riemann sums: https://brainly.com/question/23960718