Question

A ball on a string travels once around a circle with a circumference of 2.0 m. The tension in the string is 5.0 N. how much work is done by tension?

Answer 1

Answer:0

Explanation:

Given

circumference of circle is 2 m

Tension in the string $T=5 N$

$2\pi r=2$

$r=\frac{2}{2\pi }=\frac{1}{\pi }=0.318 m$

In this case Force applied i.e. Tension is Perpendicular to the Displacement therefore angle between Tension and displacement is $90^{\circ}$

$W=\int\vec{F}\cdot \vec{r}$

$W=\int Fdr\cos 90$

$W=0$

Answer 2

The work done by the ball as it travels once around the circular string is 0.

The given parameters;

• circumference of the circle, P = 2 m
• tension in the string, T = 5 N

The work-done by a body is the dot product of applied force and displacement.

For one complete rotation around the circumference of the circle, the displacement of the object is zero.

The work-done by the ball when its  makes a complete rotation around the circle is calculated as;

Work-done = F x r

where;

• r is the displacement of the ball, = 0

Work-done = 5 x 0 = 0

Thus, the work done by the ball as it travels once around the circular string is 0.

Learn more here:https://brainly.com/question/18497275