Question

Check all that apply. check all that apply. when two hydrogen atoms are very far apart, the potential energy approaches zero. when the distance between two hydrogen atoms is 0.74 å, a covalent bond is formed. when two hydrogen atoms that are far apart approach each other, the potential energy decreases. at a distance of 0.50 å the potential energy is less than that at 0.74 å. when the potential energy is zero, a covalent bond is formed.

Answer 1

Answer:

when two hydrogen atoms are very far apart, the potential energy approaches zero.

when the distance between two hydrogen atoms is 0.74 å, a covalent bond is formed.

Explanation:

As we know that the potential energy of two charges is given as

$U = \frac{kq_1q_2}{r}$

here as the the distance is very large the potential energy is least

$U = 0$

at r = infinite

so as two hydrogen atoms comes closer the distance will decrease and hence the potential energy will increase.

So covalent bond is formed when two atoms are close enough so that the equilibrium is achieved

so correct answer will be

when two hydrogen atoms are very far apart, the potential energy approaches zero.

when the distance between two hydrogen atoms is 0.74 å, a covalent bond is formed.

Answer 2

1. When two hydrogen atoms are very far apart, the potential energy approaches zero.
2. When two hydrogen atoms that are far apart approach each other, the potential energy decreases.
3. The interatomic distance between hydrogen molecules is 0.74 å, thus when the distance between two hydrogen atoms is 0.74 å, a covalent bond is formed.

The given parameters;

• distance between the atoms of the hydrogen, r = 0.74 å = 0.74 x 10⁻¹⁸ m
• distance between the atoms of the hydrogen, r =0.5 x 10 10⁻¹⁸ m

The potential energy of the hydrogen atoms is calculated as follows;

$V = \frac{kq}{r}$

where;

• k is Coulomb's constant
• q is the charge of the electron
• r is the distance between the atoms

The potential energy when the distance = 0.74 x 10⁻¹⁸ m

$V = \frac{9\times 10^{9} \times 1.602\times 10^{-19}}{0.74\times 10^{-18}} = 1.95\times 10^9 \ N.m$

The potential energy when the distance = 0.5 x 10⁻¹⁸ m

$V = \frac{9\times 10^{9} \times 1.602\times 10^{-19}}{0.5\times 10^{-18}} = 2.88 \times 10^9 \ N.m$

Thus, we can conclude that the following;

• when two hydrogen atoms are very far apart, the potential energy approaches zero.
• when two hydrogen atoms that are far apart approach each other, the potential energy decreases
• the interatomic distance between hydrogen molecules is 0.74 å, thus when the distance between two hydrogen atoms is 0.74 å, a covalent bond is formed.

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