Answer:
The slope-intercept form of both equations is [tex]y=-2x-3[/tex].
Step-by-step explanation:
The given system of equations is
[tex]2x+y=-3[/tex]
[tex]-2y=6+4x[/tex]
The slope-intercept form of an equation is
[tex]y=mx+b[/tex]
where, m is slope and b is y-intercept.
We need to write each equation in slope-intercept form.
First equation is
[tex]2x+y=-3[/tex] (Given)
[tex]y=-2x-3[/tex] (Subtract 2x on both sides)
The slope-intercept form of first equation is [tex]y=-2x-3[/tex].
Second equation is
[tex]-2y=6+4x[/tex] (Given)
[tex]y=\dfrac{6+4x}{-2}[/tex] (Divide both sides by -2)
[tex]y=\dfrac{6}{-2}+\dfrac{4x}{-2}[/tex]
[tex]y=-3-2x[/tex]
[tex]y=-2x-3[/tex]
The slope-intercept form of first equation is [tex]y=-2x-3[/tex].
Both equation have same slope intercept form it means both lines coincide each other.
So, the given system of equation have infinitely many solutions.