The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
[tex]W=(mg)h[/tex]
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
[tex]W=(1250)(2)=2500 J[/tex]
Now we can calculate the power, which is equal to the work done per unit time:
[tex]P=\frac{W}{t}[/tex]
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
[tex]P=\frac{2500}{3}=833.3 W[/tex]
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