Answer:
a) The volume increases
b) The volume decreases
c) The volume does not change
Explanation:
A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas.
When there is a change in the pressure (P) at constant temperature (T) and amount of gas (n), we can find the change in the volume (V) using Boyle's law.
P₁.V₁ = P₂.V₂
where,
1 refer to the initial state
2 refer to the final state
a) The pressure drops to 0.40 atm.
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (0.40 atm) . V₂
V₂ = 5 . V₁
The volume increases.
b) The pressure increases to 6.0 atm.
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (6.0 atm) . V₂
V₂ = 0.33 . V₁
The volume decreases.
c) The pressure remains at 2.0 atm.
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (2.0 atm) . V₂
V₂ = V₁
The volume does not change.