Respuesta :

Answer:

[tex]22\ units^2[/tex]

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a triangle plus the area of a parallelogram

Find the area of triangle KLM

[tex]A=\frac{1}{2} (b)(h)[/tex]

we have

[tex]b=7-3=4\ units[/tex] --> difference of the x-coordinates points M and K

[tex]h=6-3=3\ units[/tex] --> difference of the y-coordinates points L and K

substitute

[tex]A_1=\frac{1}{2} (4)(3)=6\ units^2[/tex]

Find the area of parallelogram JKMN

[tex]A=(B)(H)[/tex]

[tex]B=6-2=4\ units[/tex] --> difference of the x-coordinates points N and J

[tex]H=3-(-1)=4\ units[/tex] --> difference of the y-coordinates points K and J

substitute

[tex]A_2=(4)(4)=16\ units^2[/tex]

The area of the figure is equal to

[tex]A=A_1+A_2[/tex]

[tex]A=6+16=22\ units^2[/tex]

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