Answer:
[tex]22\ units^2[/tex]
Step-by-step explanation:
we know that
The area of the figure is equal to the area of a triangle plus the area of a parallelogram
Find the area of triangle KLM
[tex]A=\frac{1}{2} (b)(h)[/tex]
we have
[tex]b=7-3=4\ units[/tex] --> difference of the x-coordinates points M and K
[tex]h=6-3=3\ units[/tex] --> difference of the y-coordinates points L and K
substitute
[tex]A_1=\frac{1}{2} (4)(3)=6\ units^2[/tex]
Find the area of parallelogram JKMN
[tex]A=(B)(H)[/tex]
[tex]B=6-2=4\ units[/tex] --> difference of the x-coordinates points N and J
[tex]H=3-(-1)=4\ units[/tex] --> difference of the y-coordinates points K and J
substitute
[tex]A_2=(4)(4)=16\ units^2[/tex]
The area of the figure is equal to
[tex]A=A_1+A_2[/tex]
[tex]A=6+16=22\ units^2[/tex]