Answer:
Part 1) The lateral area is [tex]LA=210\ cm^2[/tex]
Part 2) The surface area is [tex]SA=325.5\ cm^2[/tex]
so
lateral area = 210 cm2; surface area = 325.5 cm2
Step-by-step explanation:
Part 1) Find the lateral area of the regular hexagonal pyramid
The lateral area is equal to the area of its six triangular faces
so
[tex]LA=6[\frac{1}{2}bh][/tex]
we have
[tex]b=7\ cm\\h=10\ cm[/tex]
substitute
[tex]LA=6[\frac{1}{2}(7)(10)][/tex]
[tex]LA=210\ cm^2[/tex]
Part 2) Find the surface area of the regular hexagonal pyramid
The surface area is equal to the lateral area plus the area of the hexagonal base
so
[tex]SA=LA+B[/tex]
where
B is the area of the hexagonal base
Find the area of the hexagonal base
The area of the regular hexagon is equal to the area of six equilateral triangles
[tex]B=6[\frac{1}{2}(b)(h)][/tex]
we have
[tex]b=7\ cm\\h=5.5\ cm[/tex]
substitute
[tex]B=6[\frac{1}{2}(7)(5.5)][/tex]
[tex]B=115.5\ cm^2[/tex]
The surface area is equal to
[tex]SA=210+115.5=325.5\ cm^2[/tex]