Answer:
The molecular shape and ideal bond angle of the [tex]PH_{3}[/tex] is trigonalbipyramidal and [tex]109.5^{o}[/tex] respectively.
Explanation:
The structure of [tex]PH_{3}[/tex] is as follows.(in attachment)
From the structure,
Phosphor atom has one lone pair and three hydrogens are bonded by six electrons.
Therefore, total electrons invovled in the formation [tex]PH_{3}[/tex] is eight.
Hence, four electron groups which indicate the tetrahedral shape. But one pair is lone pair i.e, present on the phosphor atom.
Therefore, ideal geometry of the [tex]PH_{3}[/tex] molecule is Trigonalbipyramidal.
The ideal angle of trigonalbipyrmidal is [tex]109.5^{o}[/tex].
All three bonds of P-H has [tex]109.5^{o}[/tex].
Therefore, ideal bond angle is [tex]109.5^{o}[/tex].