Answer:
The x-intercept is (3,0).
The vertex of the function is (3,0).
Step-by-step explanation:
Given : Function [tex]g(x)=-5(x-3)^2[/tex]
To find : What are the x-intercept and vertex of this quadratic function?
Solution :
Function [tex]g(x)=-5(x-3)^2[/tex]
The x-intercept is when g(x)=0.
i.e. [tex]-5(x-3)^2=0[/tex]
Divide by -5 both side,
[tex](x-3)^2=0[/tex]
Taking root both side,
[tex]x-3=0[/tex]
Add 3 both side,
[tex]x=3[/tex]
The x-intercept is (3,0).
The general vertex form of the quadratic function is [tex]y=a(x-h)^2+k[/tex]
where, (h,k) is the vertex
Compare the given function [tex]g(x)=-5(x-3)^2[/tex]
a=-5 , h=3 and k=0
The vertex of the function is (3,0).