Question

Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} &-9y+4x - 20=0 \\\\ &-7y+16x-80=0 \end{aligned} ​ −9y+4x−20=0 −7y+16x−80=0 ​ what is the value of x and y

Answer 1

Answer:

• (x, y) = (5, 0)

Step-by-step explanation:

$\begin{aligned} &-9y+4x - 20=0 \\ &-7y+16x-80=0 \end{aligned}$

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

Answer 2

Answer:

x=5

y=0

Step-by-step explanation: