Answer:
The zeros of the function are x=-7 and x=2
Step-by-step explanation:
we have
[tex]A(x)=(x-2)(x+7)[/tex]
we know that
The zeros or roots of the function are the values of x when the value of the function is equal to zero (also is called the x-intercepts)
so
For A(x)=0
[tex](x-2)(x+7)=0[/tex]
Remember that
The Zero Product Property states that
if ab = 0, then either a = 0 or b = 0, or both a and b are 0
so
Let
[tex](x-2)=0[/tex] ----> [tex]x=2[/tex]
[tex](x+7)=0[/tex] ----> [tex]x=-7[/tex]
therefore
The zeros of the function are x=-7 and x=2