To solve this problem it is necessary to apply the concepts related to the intensity of the sound level, which is defined by
[tex]\beta = 10log\frac{I}{I_0}[/tex]
Where,
[tex]I_ 0[/tex] = Reference Intensity [tex](10^{-12}W/m^2)[/tex]
I = Intensity
Our values are given as,
[tex]\beta_{1person}=60dB[/tex]
And if you are surrounded by 5 other people talking at the reference intensity, then we will have to,
[tex]I = 5I_0[/tex]
Then in decibels the sound level will be,
[tex]\beta_{Total} = 60dB + 10log(\frac{5I_0}{I_0})[/tex]
[tex]\beta_{Total} = 60dB + 10log(5)[/tex]
[tex]\beta_{Total} = 60dB + 10*0.7[/tex]
[tex]\beta_{Total} = 60dB + 7[/tex]
[tex]\beta_{Total} = 67dB[/tex]
Therefore the correct answer is D.