Question

How many grams of aspartame (C14H18N2O5), also known as Nutrasweet, contain 1.98×1021molecules of aspartame?

Answer 1

Answer:

0.97 grams

Explanation:

number of molecules=no of moles × Avogadros number

so

number of moles=nu.of molecules ÷ 6.02×10power23 = 1.98×10power21 ÷ 6.02×10p23=0.0033 mol

mass=nu.of moles× molar mass

molar mass of aspartame=

(14×12)+18+(2× 14.0067n)+(5×16)=294.0134 u

mass = 0.0033 ×294.0134 =0.97 gram

Answer 2

0.9675 gram/moles of aspartame is contained in $1.98 * 10^{21}$ molecules of aspartame.

How to calculate the molecular mass of aspartame in the given sample ?

We know that the Avogadro number (N) is $6.023*10^{23}$

Therefore, in $6.023*10^{23}$ molecules of sample, the amount of aspartame (C14H18N2O5) present is 294.3 g/mole .

Using simple unitary method for finding the amount of aspartame in the given sample solution -

  $6.023*10^{23}$ molecules of sample have 294.3 g/moles of aspartame.

  1 molecule of sample has $\frac{294.3}{6.023*10^{23}}$ g/moles of aspartame.

  $1.98*10^{21}$ molecule of sample has aspartame =

  $\frac{294.3}{6.023*10^{23}} * 1.98*10^{21}$ g/moles

= 0.9675 g/moles of aspartame.

Therefore 0.9675 gram/moles of aspartame (C14H18N2O5) is contained in $1.98 * 10^{21}$ molecules of aspartame.

To learn more about calculating molecular mass of compounds, refer -

https://brainly.com/question/24727597

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