Respuesta :
[tex]\dfrac{3x^2+1}{2x}=\dfrac{3x}2+\dfrac1{2x}[/tex]
Integrating this gives
[tex]\dfrac{3x^2}4+\dfrac12\ln|x|+C[/tex]
so the enthusiast's antiderivative is incorrect.
Without integrating, you can show the enthusiast's solution is incorrect by taking the derivative:
[tex]\dfrac{\mathrm d}{\mathrm dx}\left(\dfrac{x^3+x}{x^2}+C\right)=\dfrac{\mathrm d}{\mathrm dx}\left(x+\dfrac1x\right)=1-\dfrac1{x^2}=\dfrac{x^2-1}{x^2}[/tex]
but this is not the same as the original integrand.
Answer:
the enthusiast's antiderivative is incorrect
Step-by-step explanation: