Answer: 0.0016 moles
Explanation:
According to the ideal gas equation:
[tex]PV=nRT[/tex]
P = Pressure of the gas = barometric pressure - vapor pressure of water = (643-21) mm Hg = 622 mm Hg = 0.82 atm (1 atm = 760 mmHg)
V= Volume of the gas = 47.4 ml = 0.0474 L (1L=1000 ml)
T= Temperature of the gas = 23°C = 296 K (0°C = 273 K)
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas = ?
[tex]n=\frac{PV}{RT}=\frac{0.82\times 0.0474}{0.0821\times 296}=0.0016moles[/tex]
Thus the number of moles of hydrogen gas formed in the experiment was 0.0016.