Answer:
Velocity impact is 50.86 m/s.
Explanation:
If an "object of mass" "m" is dropped from "height" "h", then the "velocity" just before impact is "v" . The "kinetic energy" before impact is equal to its "gravitational potential energy" at the height from which it was dropped: Kinetic energy = J.
[tex]\mathrm{v}^{2}=2 \mathrm{gh}[/tex]
V is impact velocity
h height in meter = 132 m
[tex]\text { (gis referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }[/tex]
[tex]\mathrm{V}^{2}=2 \times 9.8 \times 132[/tex]
[tex]V^{2}=19.6 \times 132[/tex]
[tex]V^{2}=2587.2[/tex]
[tex]V=\sqrt{2587.2}[/tex]
V = 50.86 m/s
Velocity impact is 50.86 m/s.
