Question

How much heat do you need to raise the temperature of 150 g of ice from −30 °C to −15 °C ?

Answer 1

Answer : The amount of heat needed is, 9405 J

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

or,

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat required = ?

m = mass of ice = 150 g

c = specific heat of water = $4.18J/g^oC$

$T_1$ = initial temperature  = $-30^oC$

$T_2$ = final temperature  = $-15^oC$

Now put all the given value in the above formula, we get:

$q=150g\times 4.18J/g^oC\times [(-15)-(-30)]^oC$

$q=9405J$

Therefore, the amount of heat needed is, 9405 J