Respuesta :
Answer:
segment B'D' runs through O(2, 2) and is shorter than segment BD.
Step-by-step explanation:
Given quadrilateral ABCD with vertices A(1,2), B(2,3), C(4,2) and D(2,1).
The dilation with center at point O(2,2) and coefficient of dilation [tex]\frac{1}{2}[/tex] has the rule
[tex](x,y)\rightarrow \left(\dfrac{1}{2}(x-2)+2,\dfrac{1}{2}(y-2)+2\right)[/tex]
So,
- [tex]A(1,2)\rightarrow A'(1.5,2)[/tex]
- [tex]B(2,3)\rightarrow A'(2,2.5)[/tex]
- [tex]C(4,2)\rightarrow C'(3,2)[/tex]
- [tex]D(2,1)\rightarrow D'(2,1.5)[/tex]
As you can see, segment B'D' runs through O(2, 2) and is shorter than segment BD.
Segments B'D' and BD lie on the same line.

Answer:
Sorry i cant give a whole explanation but here's the answer : segment B prime D prime will run through (2, 2) and will be shorter than segment BD.
Step-by-step explanation: