Respuesta :
Answer:
Step-by-step explanation:
We want to test hypothesis:
[tex]H_0 : p\geq0.5[/tex]
[tex]H_a : p < 0.5[/tex]
This is a lower tailed test
Sample proportion. [tex]\stackrel{\wedge}{p}[/tex]=0.48, n= 331
And claimed proportion, P=0.5
Significance level, α=0.05 (if no value is given, we take level of 0.05)
Now, calculating statistics
Standard deviation of [tex]\stackrel{\wedge}{p}[/tex],[tex]\sigma_{\stackrel{\wedge}{p}}[/tex] = [tex]\frac{\sqrt{P*(1-P)}}{n}[/tex]
= [tex]\frac{\sqrt{0.05*(1-0.05)}}{331}[/tex]
[tex]\approx[/tex]0.0275
Test statistic,[tex]z_{observed }[/tex]= [tex]\frac{(\stackrel{\wedge}{p}-0.5)}{ \sigma_{\stackrel{\wedge}{p}}}[/tex]
=[tex]\frac{ ((0.48)-0.5)}{0.0275}[/tex]
[tex]\approx[/tex] -0.727736
[tex]\approx[/tex] -0.73
Test statistic: -0.73
Since this is lower tailed test, p value = [tex]P(Z < z_{observed})[/tex]= P ( Z < -0.73) = 0.2327
p-value= 0.2327
note that exact p-value is : 0.2333875382
Rejection criteria : reject H0 if p-value < [tex]\alpha[/tex]
Decision: Since[tex]p-value\geq\alpha[/tex], we fail to reject the null hypothesis. There is insufficient evidence to conclude that p is less than 0.5
Alternatively, we can use critical value approach,
[tex]Z_c= -z_\alpha=-z_{0.05}=-z_{0.05}=-1.645[/tex](From z table, using interpolation, ½th distance between -1.64 and -1.65)
critical value = -1.645
Rejection criteria: Reject[tex]H_0[/tex] if [tex]z_0< -1.645[/tex]
Decision : since [tex]z_o \geq z_c[/tex], we fail to reject the null hypothesis. There is insufficient evidence to conclude that p is less than to 0.5
The conclusion about the hypothesis test to provide evidence for the given statements; strong evidence supporting the statement that only a minority of the Americans who decide not to go to college do so because they cannot afford it
How to conduct a Hypothesis Testing?
- Step 1:
Let us state the Null hypothesis;
Null Hypothesis; H0: p = 0.5
- Step 2;
Let us state the Alternative Hypothesis;
Alternative Hypothesis; Ha: p < 0.5
- Step 3; Let us set the decision rule;
Critical value at α = 0.05 is 1.645. Thus, the decision rule is to reject the null hypothesis if the test statistic is less than -1.645 since it's a left tailed test.
- Step 4; Find the parameters;
Standard deviation is; s = √(p(1 - p)/n)
s = √(0.5(1 - 0.5)/331)
s = 0.0275
sample proportion; p^ = 0.48
population proportion; p = 0.5
- Step 5; Find the test statistic
Formula for the test statistic is gotten from the formula;
z = (p^ - p)/s
z = (0.48 - 0.5)/0.0275
z = -0.728
Step 6; Set the acceptance/rejection region;
The z-value is greater than the critical value and so we will reject the null hypothesis.
Step 7: Since we fail to reject the null hypothesis, we will conclude that the data provides strong evidence supporting the statement that only a minority of the Americans who decide not to go to college do so because they cannot afford it
Read more about creating hypothesis at; https://brainly.com/question/15980493