f(n) = f(n-1) + 1.75
f(1) = -5.25
f(2) = -5.25 + 1.75 = -3.5
f(3) = -3.5 + 1.75 = -1.75
f(4) = -1.75 + 1.75 = 0
f(5) = 0 + 1.75 = 1.75
Answer: -5.25 -3.5 -1.75 0 1.75
f(1) = - 5,25
f(n) = f(n-1) + 1,75
f(2) = f(2-1) + 1,75
= f(1) + 1,75
= - 5,25 + 1,75
= - 3,5
f(3) = - 3,5 + 1,75 = - 1,75
f(4) = - 1,75 + 1,75 = 0
f(5) = 0 + 1,75 = 1,75
The first five terms of the sequence :
- 5,25 -3,5 -1,75 0 1,75
