Respuesta :
(4x³ - 6x² - 23x + 10)/(x + 2) =
= (4x² + 8x² - 14x² - 28x + 5x + 10)/(x + 2)
= [4x²(x + 2) - 14x(x + 2) + 5(x + 2)]/(x + 2)
= (x + 2)(4x² - 14x + 5)/(x + 2)
= (4x² - 14x + 5)
Answer:
1.4 x² - 14 x + 5
2.x^3 + 3x^2 +6x +18 -1
Step-by-step explanation:
Question No 1:
4 x^3 - 6 x^2 - 23 x+10 / x+2
Factorize:
(4 x^3 + 8 x² - 14 x² - 28 x + 5 x + 10)/(x + 2)
= [4 x²(x + 2) - 14 x(x + 2) + 5(x + 2)]/(x + 2)
= (x + 2)(4 x² - 14 x + 5)/(x + 2)
cancel out x+2 then we get
=4 x² - 14 x + 5
and
by using synthetic equation we get the equation that i have attach a file where i did it by using synthetic equation you can see it.
After completing table getting the following coefficients: 4 ,-14 , 5 , 0.
4x^3 - 6x^2 - 23x+10/ x+2
x
= 4x^3– 14 x^2 -5 x
taking x common
x=x( 4x^3– 14 x^2 -5 x )
Cancel out x on both sides we get
= 4x^2– 14 x -5
Question no 2:
= x^4 - 3 x^2 - 55 /x-3
Using synthetic equation we get the equation that i have attach a file where i did it by using synthetic equation you can see it.
We complete the table an get the coffiecnt 1, 3, 6 , 18 , -1
= x^4 - 3x^2 – 55/x-3
x= x^4 +3x^3+6x^2 +18x-1
taking x common , we get
x= x(x3 + 3x2 +6x +18 -1
)
cancel out both x we get
Answer = x3 + 3x2 +6x +18 -1

