Answer:
P( A randomly selected adult has an IQ less than 126) = 0.91924
Step-by-step explanation:
Let, X be the random variable, IQ of an adult.
According to the question,
X[tex] \sim[/tex] Normal (105,15)
Let, Z = [tex]\frac {X - 105}{15}[/tex]
So, Z [tex]\sim [/tex] Normal(0,1)
Now,
X < 126
⇒[tex]\frac {X - 105}{15}[/tex] < [tex]\frac {21}{15}[/tex]
⇒Z < 1.4
Now, from standard normal probability table we get
P(Z < 1.4) = 0.91924
So, P( A randomly selected adult has an IQ less than 126) = 0.91924