Question

A cylinder has a radius of 2 inches and a height of 5 inches. A sphere has a
radius of 2 inches. What is the difference between the volumes, to the
nearest tenth of a cubic inch, of the cylinder and the sphere?

Answer 1

Answer:

$29.3\ in^3$

Step-by-step explanation:

step 1

Find the volume of the cylinder

we know that

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$r=2\ in\\ h=5\ in$

substitute

$V=\pi (2^{2})(5)$

$V=20\pi\ in^3$

step 2

Find the volume of the sphere

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=2\ in$

substitute

$V=\frac{4}{3}\pi (2)^{3}$

$V=\frac{32}{3}\pi\ in^3$

step 3

Find the difference of volumes

$20\pi\ in^3-\frac{32}{3}\pi\ in^3=\frac{28}{3}\pi\ in^3$

assume

$\pi =3.14$

substitute

$\frac{28}{3}(3.14)=29.3\ in^3$