Question

what is the probability of rolling a four then a three

Answer 1

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY=$\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability=$\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$.

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability=$\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll=$\frac{1}{6}$

probability to get 3 in second roll=$\frac{1}{6}$

probability to occur both at a same time is =$\frac{1}{6}$ $\times$$\frac{1}{6}$=$\frac{1}{36}$