Respuesta :

Answer:

[tex]y=Ae^{-2x}[/tex]

Step-by-step explanation:

Given that the functions f(x) that have the property that the tangent lines to the graphs of f(x)pass through the point (x+2,0).

Let (x,y) be any arbitrary point of contract

The tangent line passes through two points (x,y) and (x+2,0)

Slope of tangent line = f'(x) = change in y/change in x= [tex]\frac{-y}{2}[/tex]

i.e. we have

[tex]\frac{dy}{dx} =\frac{-y}{2}[/tex]

Separate the variables

[tex]\frac{dy}{y} =-2x\\lny =-2x+c[/tex]

Raise to power e

[tex]y=Ae^{-2x}[/tex]

Thus the functions would have the above form for various values of A

ACCESS MORE
EDU ACCESS