Answer:
[tex]y=Ae^{-2x}[/tex]
Step-by-step explanation:
Given that the functions f(x) that have the property that the tangent lines to the graphs of f(x)pass through the point (x+2,0).
Let (x,y) be any arbitrary point of contract
The tangent line passes through two points (x,y) and (x+2,0)
Slope of tangent line = f'(x) = change in y/change in x= [tex]\frac{-y}{2}[/tex]
i.e. we have
[tex]\frac{dy}{dx} =\frac{-y}{2}[/tex]
Separate the variables
[tex]\frac{dy}{y} =-2x\\lny =-2x+c[/tex]
Raise to power e
[tex]y=Ae^{-2x}[/tex]
Thus the functions would have the above form for various values of A