Respuesta :
Answer:
- Micha's average velocity for her run north, v₁ = 6.06 miles/hr
- Micha's average velocity for the whole trip, V = - 0.32 miles/hr
- The speed of her jog is, s = 3.03 miles / hr
Explanation:
Given data,
The distance Micha run towards the north, d₁ = 2 miles
The time taken by Micha to run 2 miles is, t₁ = 20 min
= 0.33 h
The displacement towards the south, d₂ = -1 mile
The running duration, t₂ = 15 min
= 0.25 h
Walked displacement, d₃ = -1 mile
The time period to cover that distance, t₃ = 0.33 h
1) The average velocity towards north,
v₁ = d₁ / t₁
= 2 / 0.33
= 6.06 miles/hr
Hence, Micha's average velocity for her run north, v₁ = 6.06 miles/hr
2) The average velocity for whole trip,
V = (v₁ + v₂ + v₃) / 3
The velocity towards south,
v₂ = d₂ / t₂
= -1 / 0.25 h
= -4 miles / hr
The walked velocity,
v₃ = d₃ / t₃
= -1 / 0.33
= - 3.03 miles/hr
∴ The average velocity,
V = (v₁ + v₂ + v₃) / 3
= (6.06 - 4 -3.03)/3
= - 0.32 miles/hr
Hence, Micha's average velocity for the whole trip, V = - 0.32 miles/hr
3) The average speed for her entire jog,
The velocity of her jog, v₃ = - 3.03 miles/hr
∴ Speed,
s = |v|
= 3.03 miles / hr
Hence, the speed of her jog is, s = 3.03 miles / hr
