Answer:
star B will appear 1/25 = 0.04 times compared to star A
star b will look smaller from star A
Explanation:
star A is at a distance of 5 pc
star B is at a distance of 25 pc
How will star B appear, compared with star A?
the inverse square law of light for apparent brigthness, b =
b= L/(4πd²)
where, L is the luminiosity = light output
d = distance
L₁/(4πd₁²) = L₂/(4πd₂²)
since L, is constant
d₁² = d₂²
5² = 25²
[5/25]² = [1/5]² = 1/25
star B will appear 1/25 = 0.04 times compared to star A
star b will look smaller from star A
