Answer:
The value of X in the solution to the system of linear equations below
5x-4=3y
2x+32= 4y is 8.
Step-by-step explanation:
Solution:
First write the expression in the form of ax by = c
Therefore the equations are as
[tex]5x-3y=4\ and\\2x-4y=-32[/tex]
Now we will write in linear equation in matrix form
[tex]\left[\begin{array}{cc}5&-3\\2&-4\end{array}{}\right] \left[\begin{array}{c}x\\y\end{array}{}\right]= \left[\begin{array}{c}4\\-32\end{array}{}\right][/tex]
By Cramer's rule we have
[tex]x = \frac{Dx}{D}[/tex]
Where D is the determinant of 2 x 2 matrix
and Dx is the determinant after replacing the x coefficient by the constants
[tex]Det\left[\begin{array}{cc}5&-3\\2&-4\end{array}{}\right]= 5\times-4-(-3\times2)\\\\=-20+6\\\therefore D= -14\\[/tex]
For Dx we will have
[tex]Dx= \left[\begin{array}{cc}4&-3\\-32&-4\end{array}{}\right]= 4\times-4-(-3\times -32)\\\\=-16-96\\= -112\\\therefore Dx = -112[/tex]
Now by Cramer's rule
[tex]x = \frac{Dx}{D}\\= \frac{-112}{-14}\\= 8\\ \therefore x = 8[/tex]