A 20 dBm power source is connected to the input of a directional coupler having a coupling factor of 20 dB, a directivity of 35 dB, and an insertion loss of 0.5 dB. If all ports are matched, find the output powers (in dBm) at the through, coupled, and isolated ports.

Respuesta :

Answer:

[tex]P_O = 0.989 watt = 19.9 dBm[/tex]

Explanation:

Given data:

P_1 power = 20 dBm  = 0.1 watt

coupling factor is 20dB

Directivity = 35 dB

We know that

coupling factor [tex] = 10 log \frac{P_1}{P_f}[/tex]

solving for  final power

[tex]20 = 10 log\frac{P_1}{P_f}[/tex]

[tex]2 = log \frac{P_1}{P_f}[/tex]

[tex]100 = \frac{0.1}{P_f}[/tex]

[tex]P_f = 0.001 watt = 0 dBm[/tex]

Directivity [tex]D =  10 \frac{P_f}{P_b}[/tex]

[tex]35 = 10 \frac{0.001}{P_b}[/tex]

[tex]P_b = 3.162 \times 10^{-7} wattt[/tex]

output Power  [tex]= P_1 -P_f - P_b[/tex]

                       [tex] = 0.1 - 0.001 - 3.162 \times 10^{-7}[/tex]

[tex]P_O = 0.989 watt = 19.9 dBm[/tex]

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