Answer:
[tex]W_{h}= 4.275yd[/tex]
Step-by-step explanation:
Data
wide=20yd
length=40yd
Hedge area [tex]A_{h}[/tex]=[tex]171yd^{2}[/tex]
If the area of rectangle is A=base * hight and our case L*W. then:
[tex]A_{h}=171yd^{2}=40yd*W_{h}[/tex]
So [tex]W_{h}=\frac{A_{h} }{L} =171yd^{2}/40yd=4.275yd[/tex]