Answer:
837.554256 N
Explanation:
[tex]F_N[/tex] = Normal force
m = Mass of stuntman = 96.8 kg
g = Acceleration due to gravity = 9.81 m/s²
[tex]\mu[/tex] = Coefficient of kinetic friction = 0.882
T = Tension
[tex]f_k[/tex] = Frictional force
In the vertical direction
[tex]F_N-mg=0\\\Rightarrow F_N=mg\\\Rightarrow F_N=96.8\times 9.81\\\Rightarrow F_N=949.608\ N[/tex]
In the horizontal direction
[tex]T-f_k=0\\\Rightarrow T=f_k\\\Rightarrow T=\mu F_N\\\Rightarrow T=0.882\times 949.608\\\Rightarrow T=837.554256\ N[/tex]
The tension in the cable is 837.554256 N
